At what height would a water riser with an initial pressure of 110 p.s.i.g. experience a pressure of approximately 80 p.s.i.g.?

To determine the height at which the pressure in a water riser drops from 110 p.s.i.g. to approximately 80 p.s.i.g., it is necessary to understand how pressure changes with elevation in a fluid column, governed by the hydrostatic pressure formula.

The pressure change in a fluid due to elevation can be expressed using the formula:

[

\Delta P = \rho \cdot g \cdot h

]

Where:

• (\Delta P) is the change in pressure (in pounds per square inch),

• (\rho) is the density of the fluid (for water, approximately 62.4 lbs/ft³),

• (g) is the acceleration due to gravity (approximately 32.2 ft/s²),

• (h) is the height in feet.

In this case, the difference in pressure is:

[

\Delta P = 110 \text{ p.s.i.g.} - 80 \text{ p.s.i.g.} = 30 \text{ p.s.i.}

]

To convert pressure loss in p.s.i. to height in feet, you can use the fact that every 2.31 feet of height (for